18x^2+8x-19=0

Solution for 18x^2+8x-19=0 equation:

18x^2+8x-19=0

a = 18; b = 8; c = -19;
Δ = b2-4ac
Δ = 82-4·18·(-19)
Δ = 1432
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1432}=\sqrt{4*358}=\sqrt{4}*\sqrt{358}=2\sqrt{358}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-2\sqrt{358}}{2*18}=\frac{-8-2\sqrt{358}}{36}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+2\sqrt{358}}{2*18}=\frac{-8+2\sqrt{358}}{36}
$